What does the green left-bottom path have to do with fetch mode?
Maybe I missed it in Dvir’s recitation but I have watched it again and I still don’t understand it.
If I get it right, first the PC needs to output the next instruction’s address, and only then it can be sent to the IR. How can this happpen within one clock cycle?
Assuming the clock cycle is long enough, this can be done in one cycle. We haven’t learned timing analysis this year, so this might seem a bit off but the main idea can be understood with the tools we gave (t_pd and t_cont).