In RAM, if I define R / not-write == 1 (which means I’m writing in D_in(t) ) - is the value coming out is Q(t) (that equals to D_in(t-1)) or is it non-logic?
In RAM, if I define R / not-write == 1 (which means I’m writing in D_in(t) ) - is the value coming out is Q(t) (that equals to D_in(t-1)) or is it non-logic?